Question

The 6th and 17th term of an A. P are 19 and 41 respectively find the 40th term

Answer 1

Answer:

(a.n.) = a+(n-1)d

a6= a+5d

a17= a+16d

Step-by-step explanation:

now put nos. in the formula and u can solve easily.

Answer 2

Given :-

6th term - 19

17th term - 41

To find :-

40th term

➜ 6th term,. a+5d = 19 ....(1)

17th term,. a+16d = 41 ........(2)

Subtract (1)&(2)

a+5d=19

- a-16d=-41

-11d = -22

d = 22/11

d = 2

Putting it in eqn (1)

a+5(2)=19

a+10=19

a=19-10

a=9

Now for 40th term,

an = a+(n-1)d

= 9+(40-1)2

= 9+80-2

= 7+80

= 87

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