The 6th and the 17th terms of an AP are 21 and 54 respectively . Find the 40th term
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Step-by-step explanation:
a+5d=21 ----- (1)
a+16d=54----(2)
subtract (1) from (2)
11d=33
d=3 substitute d in equation to get a value
a+5×3=21 ; a=6
40th term =a+39d
=6+39×3
therefore; 40th term of an A.P is 123
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