Question

the 6th question. plsss answer irrelevant answers will be reported ​

Answer 1

Given :-

Distance covered by body in 4th second = 24 m.

Distance covered by body in 6th second = 36 m.

${S}_{4} = 24 \: m$

u + a/2 (2n-1) = 24

u + a/2 (2×4 -1) = 24

u + 7a/2 = 24 -----(1)

Again,

${S}_{6} = 36 \: m$

u + a/2(2 × 6 -1) = 36

u + 11a/2 = 36 ------(2)

Subtracting equation (1) from equation (2)

u + 11a/2 = 36

u + 7a/2 = 24

- - -

______________

4a/2 = 12

a = 6 ms-²

Putting the value of 'a' in equation (1).

u + 7 × 6/2 = 24

u = 24 - 42/2

u = 24 - 21

u = 21 ms-¹

Hence,

Acceleration of the body = a = 6 ms-²

Velocity of the body = v = 3 ms-¹

Answer 2

Answer:

Given :-

Distance covered by body in 4th second = 24 m.

Distance covered by body in 6th second = 36 m.

{S}_{4} = 24 \: mS

4

=24m

u + a/2 (2n-1) = 24

u + a/2 (2×4 -1) = 24

u + 7a/2 = 24 -----(1)

Again,

{S}_{6} = 36 \: mS

6

=36m

u + a/2(2 × 6 -1) = 36

u + 11a/2 = 36 ------(2)

Subtracting equation (1) from equation (2)

u + 11a/2 = 36

u + 7a/2 = 24

- - -

______________

4a/2 = 12

a = 6 ms-²

Putting the value of 'a' in equation (1).

u + 7 × 6/2 = 24

u = 24 - 42/2

u = 24 - 21

u = 21 ms-¹

Hence,

Acceleration of the body = a = 6 ms-²

Velocity of the body = v = 3 ms-¹