Question

The 6th term from the end of the AP: 5, 2, -1, -4, …., -31, is

-25
-22
-19
-16​

Answer 1

Given:-

• An A.P 5, 2, -1, -4, …., -31.

To Find:-

• 6th term from the end of the AP.

Formula Used:-

• ${\boxed{\bf{a_n=a+(n-1)d}}}$

Solution:-

Given A.P :- 5, 2, -1, -4, …., -31.

We have to find the 6th term from the end. To Find it we will reverse the A.P to make it easier to find.

Reversed A.P :- -31, ...., -4, -1, 2, 5.

Using Formula,

$\sf :\implies\:a_n=a+(n-1)d$

Here,

• a = -31
• n = 6
• d = 5 - 2 = 3

Putting Values,

$\sf :\implies\:a_n=-31+(6-1)3$

$\sf :\implies\:a_n=-31+5\times 3$

$\sf :\implies\:a_n=-31+15$

$\sf :\implies\:a_n=-16$

Hence, The 6th term from the end of the given A.P is -16.

[ Option 4 is correct ].

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Answer 2

Step-by-step explanation:

option 4 -16 is the answer