Math, asked by maryjanechidera, 10 months ago

The 6th term of a Gp is -2/27 and the first term is 18. what is the common ratio.

Answers

Answered by diya6152
0

Answer:

Maths keeps one mentally active. The 3rd term of the GP is ar^2 = 18 and the 6th term, ar^5 = 486. a, the first term is 2 and the common ratio, r = 3.

Answered by AirSniper
4

Answer:

-1/3

Step-by-step explanation:

step 1:-  n^{th} term of GP is T_{n} = a*r^{n-1}   where  a = first term of GP & r =  common ratio

step 2:- From given data 6^{th} term is -2/27

             Hence ,  n = 6 ; T_{6} = -2/27 ; a =18;

step 3 : -  T_{n} = a*r^{n-1}  

              by replacing values

                \frac{-2}{27} = 18*r^{6-1} ;

                 r^{5} = \frac{-2}{27 * 18}  ;

                  r^{5} = \frac{-1}{27 * 9}   ;

                    r^{5} = \frac{-1}{243}  ;

                   r = \frac{-1}{3}   ( As 3^{5} = 243 , divide both side by 5^{th} root)

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