the 6th term of an A.P is 36 and the 4th term is 24. find the 10th term
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Heya !!!
6th term = 36
A + 5D = 36-----------(1)
And,
4th term = 24
A + 3D = 24 -----------(2)
From equation (1) we get,
A+ 5D = 36
A = 36-5D ---------(3)
Putting the value of A in equation (2)
A + 3D = 24
36-5D +3D = 24
-2D = 24-36
-2D = -12
D = -12/-2 = 6
Putting the value of D in equation (3)
A = 36-5D => 36 -5 × 6 => 36-30
A = 6
Therefore,
First term (A) = 6
And,
Common difference (D) = 6
10th term = A + 9D = 6 + 9 × 6 = 6 + 54 = 60
HENCE,
10TH TERM IS 60.
HOPE IT WILL HELP YOU....... :-)
6th term = 36
A + 5D = 36-----------(1)
And,
4th term = 24
A + 3D = 24 -----------(2)
From equation (1) we get,
A+ 5D = 36
A = 36-5D ---------(3)
Putting the value of A in equation (2)
A + 3D = 24
36-5D +3D = 24
-2D = 24-36
-2D = -12
D = -12/-2 = 6
Putting the value of D in equation (3)
A = 36-5D => 36 -5 × 6 => 36-30
A = 6
Therefore,
First term (A) = 6
And,
Common difference (D) = 6
10th term = A + 9D = 6 + 9 × 6 = 6 + 54 = 60
HENCE,
10TH TERM IS 60.
HOPE IT WILL HELP YOU....... :-)
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