The 6th term of an AP exceeds its 3rd term by 21 and its first term is 12. Its 20th term is
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a6 = a3+21
a = 12
a +5d = a +2d +21
3d = 21
d = 7
a 20 = a+19d
= 12+19*7
= 12+133
=145
Therefore a20 = 145
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Answered by
0
a+5d=a+2d+21
3d=21
d=7
a=12
20 th term=12+19(7)
12+153
176
hope it is right
3d=21
d=7
a=12
20 th term=12+19(7)
12+153
176
hope it is right
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