The 6th term of an AP is 0.Prove that it's 21st term is triple it's 11th term
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Step-by-step explanation:
t6=a+5d
a+5d=0...(1)
t11=a+10d
i.e. t11=a+5d+5d...(2)
t21=a+20d
i.e. t21=a+5d+15d...(3)
But a+5d=0..(from (1) ).
t11=5d and t21=15d.
Hence t21=3t11
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so this the process
NORMAL QUESTION
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