The 6th term of an AP is 1 more than twice its 8th term if the 12th term of the AP is 47 then find n th term.
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Let us assume that a and d are first term and common difference of the AP respectively.
Given that the 6th term of an AP is 1 more than twice the 8th term.
lt give one equation in the form of a and d .
and also given that 12th term of that ap is 47 which give second equation in a and d .
After solving these two equations simultaneously we will get the values of a and d respectively .
After then we will put those values of a and d in the formula of calculating and its term of an AP as shown in attachment .
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Answered by
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a6 = a + 5d
a8 = a + 7d
Now,
a + 5 d = 2 ( a+7d) + 1
=> a + 5d =( 2a + 14 d) + 1
=> a + 9 d = -1
a12 = a + 11d = 47
a = - 217
d = 24
an = a + (n-1)d
= -217 + (n -1)24
= -217 + 24n - 24
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