Question

the 6th term of an ap is -10 and it's 10th term is -26.Determine the 15th term of the ap

Answer 1

Here is your answer.
Given:
a6 = - 10
a + 5d = - 10............. 1
And, a10 = - 26
a + 9d = - 26............2
Subtracting 1 from 2
4d= - 16
d = - 4
Putting d =-4 in 1
a + 5(-4) = - 10
a = 10

a15 = a + 14d
= 10 + 14( - 4)
= - 46

Answer 2

hi mate here is ur answer

given the 6th term = -10

tn = a + ( n- 1)d

here given is t6

so the equation is as follows

t6 = a + ( 6-1)d

t6 = a + 5d equation 1

now for t10

t10 = a + ( 10 - 1) d

t10 = a + 9d  equation 2

from 1 and 2

a + 5d = -10

a + 9d = -26

subtracting the both we get

-4d = 16

d = -4

now substituting the value of d in equation 1

we get , a + 5 ( -4) = -10

a + ( -20) = -10

a - 20 = -10

a = -10 + 20

a = 10

now for the value of the 15th term we get

t15 = a + ( 15-1) d

t15 = 10 + 14 x -4

t15 = 10 + (-56)

t15 = 10 - 56

t15 = -46

hope it helps you

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