the 6th term of an AP is 4 times the 2nd term and the sum of the first 24 terms is 1704. find the sum of the first 49 terms?
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Answer:
7056
Step-by-step explanation:
let first term be a.
let common difference be d.
the 6th term of an AP is 4 times the 2nd term
a + 5d = 4(a+d)
a+5d = 4a+4d
3a=d
sum of the first 24 terms is 1704.
24/2(2a+23d)=1704
12(2a+69a)=1704
a = 1704/(12*71)=2
d=3a=6
Sum of first 49 terms = 49/2(2a+48d)=49*(a+24d)=49*144=7056
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