Question

the 6th term of an ap is 47 and 14th term of ap is 111 find the common difference and the 20th term​

Answer 1

Answer:

d = 8 , 20th = 152

Step-by-step explanation:

a + 13d = 14th term

a + 5d = 6th term

a +13d = 111 - (1)

a + 5d = 47 - (2)

d = 8

a = 7 ( by substituting d = 8 in 2)

20th term = a +19d

= 152

Answer 2

Answer:

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Step-by-step explanation:

Given: 6th term A6= 20, 11th term A11=30

we have, An= A1+(n-1)d

=> A6=A1+(6–1)d

=> 20=A1+5d ——equation (1)

A11=A1+(11–1)d

=> 30=A1+(11–1)d

=> 30= A1+10d ——equation (2)

equating 1 and 2, we have

=> d=2, substitute in eq(1)

=> 20= A1+5(2)

=>A1=20–10=10

Hence, the first term A1=10 and common difference d=2.