the 6th term of an AP is zero. prove that its 21st term is triple its 11th term
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Hey friend, ☺ here is ur answer __________________________
a6 = 0
a + 5d = 0 .....…....(1)
a21 = a + 20d
= a + 5d + 15d
= 0 + 15d ( from (1) )
a21 = 15d
a11 = a + 10d
= a + 5d + 5d
= 0 + 5d ( from (1) )
a11 = 5d...............(2)
we can also write a21 as :-
a21 = 15d
= 3 × 5d
a21 = 3 + a11. from (2)
hence proved
a6 = 0
a + 5d = 0 .....…....(1)
a21 = a + 20d
= a + 5d + 15d
= 0 + 15d ( from (1) )
a21 = 15d
a11 = a + 10d
= a + 5d + 5d
= 0 + 5d ( from (1) )
a11 = 5d...............(2)
we can also write a21 as :-
a21 = 15d
= 3 × 5d
a21 = 3 + a11. from (2)
hence proved
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