Question

The 6th term of an AP is zero. Prove that the 30th term of the AP is 3 times its 14th term.

Answer 1

Answer:

Answer refer to the Given attachment. ......

Hope it helps

Answer 2

Answer:

Step-by-step explanation:

an = a +(n -1) d

a6 = a + (6-1)d

a6 = a +5d……………(1)

a30 = a +(30-1)d

a30 = a +29d………(2)

a14 = a + (14-1)d

a14 = a +13d……………(3)

a6 = a +5d

0 = a +5d    (given)

a= -5d

a30 = a +29d

a30 = -5d +29d

a30 = 24d

a30 = 3(8d)..................(4)

a14 = a +13d

a14 = -5d +13d

a14 = 8d………………..(5)