The 6thterm of an A.P is -10 and its 10thterm is -26. Determine the 15thterm of an AP
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Answered by
1
Answer
Tn=a+(n-1)*d
Hence for 6th term we use this formula
T6=a+ (6-1)*d
Like this for 10 term
T10 = a+ 9 *d..
A.T.Q
a+5d=-10
a+9d= -26
Solve simultaneously both equation
By simply subtracting it
We get
a=10 .
d= -4.
Hence
t 15= a+14*d
T15= 10+14*(-4)
T15= -46
This answer
Step-by-step explanation:
Answered by
1
Answer:
-46
Step-by-step explanation:
given a6=(-10)
a10=(-26)
a6= a+ 5d (1)
a10=a+9d (2)
(1)-(2) _ 16= {-4}d
therefore d={-4}and a=10
implies a15=a+14d
=10+(-56)={-46}
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