the 7 term of an A.P.is 32 and 13 term is 62 .find the A.P.
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given
7th term = 32
which means a+6d=32 .......(1)
13th term+62
which means a+12d=62 ......(2)
subtracting 1 from 2
a+12d-a-6d=62-32
6d=30
d=5
a+6d=32
a+30=32
a=2
a2=7
7th term = 32
which means a+6d=32 .......(1)
13th term+62
which means a+12d=62 ......(2)
subtracting 1 from 2
a+12d-a-6d=62-32
6d=30
d=5
a+6d=32
a+30=32
a=2
a2=7
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