the 7 term of an A.P. is 32 and 13 term is 62. find the A.P.
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We have,
t7=a+6d
or,32=a+6d...(i)
Now,t13=a+12d
or,62=a+12d...(ii)
Again,By solving i and ii ,we get,
a=2 and d=5
So,the required A.P.is 2,7,12,18,.......
t7=a+6d
or,32=a+6d...(i)
Now,t13=a+12d
or,62=a+12d...(ii)
Again,By solving i and ii ,we get,
a=2 and d=5
So,the required A.P.is 2,7,12,18,.......
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