Question

the 7 term of an A,P is 32 and 13th term is 62 find the A.P

Answer 1

ok the 7th term can be written :
a+6d = 32
13th term:
a+12d= 62
now equating both the equations
we get 6d= 30
d= 5
now putting the value of d ,
a+ 6*5= 32
so a= 32-30
a= 2
next term a+d = 7 and so on
so now we can write the AP as
2, 7, 12, 17, 22, 27, 32,37.......

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Answer 2

T7 = a+6d = 32
T13=a +12d = 62

then,
6d = 30
d = 5

similarly,
a= 32-30
=2
as a =2 & d=5
required A.P is
2,7,12,17,22,27,32,37..........................