The 7 term of an AP is 32 and its 12 term is 57 find the AP
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Step-by-step explanation:
aₙ=a+(n-1)d
so,
a₇=a+(7-1)d=32
=>a+6d=32 ...(i)
a₁₂=a+(12-1)d=57
=>a+11d=57 ...(ii)
subtracting equation (1) from (ii)
a+11d=57
a+6d=32
- - -
________
5d=25
=>d=25÷5=5
putting the value of d in equation (ii)
a+11d=57
=>a+11(5)=57
=>a=57-55=2
so,the AP is
a=2
a₂=a+(n-1)d=2+5=7
a₃=a+(n-1)d=2+2(5)=12
a₄=a+(n-1)d=2+3(5)=17
a₅=a+(n-1)d=2+4(5)=22
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