the 7 th term of an is -4 and it's 13 th is -16. find the Ap
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Solution:
⟩ t7 = - 4...(1) & t13 = - 16...(2)
» d = (t13 - t7)/(13 - 7)
» d = -12/6
» d = - 2
Substituting in (1) we get
» a = 8
Therefore, the required A.P. is 8, 6, 4,...
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