the. 7term of an ap is 32 and 13 term is 62 find the ap
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We know that the Term n of an AP = a + (n - 1)d where a = first term of AP and d = common difference
Term 7 = 32 => a + 6d = 32 ....... eqn 1
Term 13 = 62 => a + 12d = 62 .......eqn 2
Solving both equations simultaneously , we get a = 2 and d = 5
AP : a, a+d , a+2d , .....
AP: 2, 7, 12 , 17 , 22 , 27, 32 ..........
Term 7 = 32 => a + 6d = 32 ....... eqn 1
Term 13 = 62 => a + 12d = 62 .......eqn 2
Solving both equations simultaneously , we get a = 2 and d = 5
AP : a, a+d , a+2d , .....
AP: 2, 7, 12 , 17 , 22 , 27, 32 ..........
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