Question

the 7th and 17th term of an arithmetic progression are 33 and 83 respectively find the ap​

Answer 1

Answer:

$a7 = a + 6d = 33 - - - (1)$

$a17 = a + 16d = 83 - - - (2)$

subtract 1 from 2

16d-6d=83-33

10d=50

•°• d=5

put d in equation 1

a+6(5)=33

a+30=33

•°• a=33-30=3

AP a,a+d, a+2d, a+3d-------

a=3

a+d=3+5=8

a+2d=3+2 (5)=3+10=13

a+3d=3+3 (5)=3+15=18

•°• AP is 3,8,13,18-----