Question

the 7th term and 13th terms of an AP are 34 respectively .find the first three terms​

Answer 1

Answer:

question not properly 13th term not fill in question, put I put behalf me. use only this method, you put your value.

answer:-22,24,26

Explanation:

An= a+(n-1) d

7th term for= a+6d

34=a+6d

a= 34-6d........(1)

13th term= a+12d

13th term not available so I put for behalf me= 56 and you put right value

=a+12d.....(1)

put value of a from...... (1)

so, 56= 34-d+12d

56= 34+11d

11d=56-34

d=22÷11=2

d=2 put in... (1)

so a= 34-6(2)

a= 34-12=22

first three term are 22,24,26