Question

the 7th term from the end of the AP - 11 - 8 - 5, to 49​

Answer 1

Step-by-step explanation:

AP: -11,-8,-5...49

a=-11

D= t2- t1

=-8-(-11)

=3

tn=a+(n-1)d

49=-11+(n-1)(3)

49=-11+3n-3

49=-13+3n

(49+13)/3=n

n=62/3

n=31

the last seventh term is

n-7=31-7

= 24

please correct my mistakes if any

Answer 2

Answer:

31

Step-by-step explanation:

Your answer is in attachment