the 7th term of an A.P. is 32 and 13th term is 62 . Find the A.P.
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Here is your solution
a+6d=32, .............. (1)
a+12d=62................... (2)
on subtracting equation 1 from. ii
a+12d-a-6d=62-32
6d= 30
d=5
hence, a=2
Ap are 2,2+5,2+5+5,2+5+5+5
Ap are 2,7,12,17
hope it helps you
a+6d=32, .............. (1)
a+12d=62................... (2)
on subtracting equation 1 from. ii
a+12d-a-6d=62-32
6d= 30
d=5
hence, a=2
Ap are 2,2+5,2+5+5,2+5+5+5
Ap are 2,7,12,17
hope it helps you
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