Question

the 7th term of an A.P. is 32 and 13th term is 62 . find the A.P.

Answer 1

a+6d=32...1)
a+12d=62...2)
now sub 1)Nd 2)
them we get
d=5 and a=2 so
ap 2,7,12,17.....

Answer 2

hello Harpreet

here is your answer

Given that

$a_{7} = 32 \\ a_{13} = 62$
As we know

a + 6d = 32 ...............(1)
a + 12d = 62...............(2)

Now, (2) - (1)

a + 12d - a - 6d = 62 - 32
6d = 30
d = 5

d = 5 putting in (1)

a + 6 ( 5) = 32
a + 30 = 32
a = 2

Now, we have a = 2 and d = 5

Required AP is

2, 7, 12,17 ....



hope it helps
jerri