Question

The 7th term of an A.P. is 32 and 13th term is 62. find the A.P

Answer 1

let a,a+d, a+2d,... are in AP
A/Q
T7= a+6d=32
T13= a+12d=62
by solving the equation
we get d=5
put in 1 equation we get, a=2
so AP is 2, 7, 12...

Answer 2

Here is your solution

a+6d=32, .............. (1)
a+12d=62................... (2)

on subtracting equation 1 from. ii

a+12d-a-6d=62-32
6d= 30
d=5

hence, a=2

Ap are 2,2+5,2+5+5,2+5+5+5

Ap are 2,7,12,17

hope it helps you