the 7th term of an A.P is 32 and 13th term is 62. find the A.P.
Answers
Answered by
287
a + 6d=32
a+ 12d=62
by solving both equation we get
d = 5 & a= 2
Then A.P will be as follows:
2,7,12,17,22,27,32,37,42,47,52...................
a+ 12d=62
by solving both equation we get
d = 5 & a= 2
Then A.P will be as follows:
2,7,12,17,22,27,32,37,42,47,52...................
Answered by
456
an = a+ (n-1)d
Now, a7= a+6d = 32---------------(1)
a13= a+ 12d =62-------------------(2)
Subtracting (1) and (2)
-6d = (-30)
d = 5
Putting the value of 'd ' in (1)
a + 6 (5) = 32
a + 30 = 32
a = 32- 30
a = 2, d = 5
So, the required A.P is 2, 7, 12, 17,22.......
Hope it helps you !!
Now, a7= a+6d = 32---------------(1)
a13= a+ 12d =62-------------------(2)
Subtracting (1) and (2)
-6d = (-30)
d = 5
Putting the value of 'd ' in (1)
a + 6 (5) = 32
a + 30 = 32
a = 32- 30
a = 2, d = 5
So, the required A.P is 2, 7, 12, 17,22.......
Hope it helps you !!
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