the 7th term of an A.P is 32 and it's 13th term is 62 find the 10th term of that A. P
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Let term 1 be a
Common difference be d
A. T. Q. =
7th term =a ➕ 6d = 32 ..... 1
13th term =a ➕ 12d = 62 ...... 2
Using equation 1 and 2
(a ➕ 6d =32) ➕ (a ➕ 12d =62)
= d = 30 ÷ 5
= d = 6
Now,
a ➕ 6d = term 7
= a ➕ (6 • 5) = 32
=a = 32 ➖ 30
= a = 2
Now,
term 10 = a ➕ 9d
= 2 ➕ ( 9 • 5)
= 2 ➕ 45
= 47
Hence, the 10th term of the AP is 47.
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