Question

The 7th term of an A.P. is 32 and its 13th term is 62.Find the A.P.​

Answer 1

Answer:

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Answer 2

Given:

7th term = 32

a + 6d = 32 -------(i)

13 term = 62

a + 12d = 62 -------(ii)

Subtract (i) from (ii), we get

a + 12d - a - 6d = 62 - 32

12d - 6d = 30

6d = 30

d = 5

Put value of d in eq(i)

a + 6d = 32

a + 6(5) = 32

a + 30 = 32

a = 32 - 30

a = 2

A.P = a, a + d, a + 2d, a + 3d ,....

2 , 2 + 5 , 2 + 10 , 2 + 15 , ...

A.P = 2 , 7, 12 , 17 , ...