Question

the 7th term of an a.p is 32 and its 13th term is 62 find the a.p

Answer 1

Answer:

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Step-by-step explanation:

a₇ = 32

a + (7 - 1) d = 32

a + 6d = 32_____(i)

a₁₃ = 62

a + (13 - 1) d = 62

a + 12d = 62_____(ii)

Solving equation (i) and (ii),

a-a+12d-6d=62-32

6d = 30

d = 5

Putting d = 5 in equation (i),

a + 6 (5) = 32

a + 30 = 32

a = 32 - 30

a = 2

We found that a = 2 and d = 5

Thus, the required AP is

= a, a + d, a + 2d, a + 3d,...

= 2, 2 + 5, 2 + 2(5), 2 + 3(5),...

= 2, 7, 2 + 10, 2 + 15,...

= 2, 7, 12, 17,...