Question

The 7th term of an A.P is -39/12 and the 15th term is -103/12.what is the 27th term

Answer 1

Answer:

a7 =,-39/12

a15=-103/12

a+6d=39/12.................(1)

a+14d=103/12..............(2)

subtract the equation 1 from 2

a +14d=103/12

a+6d=39/12

- - -

8d =103/12-39/12

8d =103-39÷12

8d =64÷12

8d = 16÷3

d = 16/3/8

d=16 × 1

3 8

d=16

24

d=4

6

d=2

3

a+6d=–39

12

a+6×2=–39

3 12

a+4 =–39

12

a+4×12=–39

a+48=–39

a=–39–48

a=-9

= a+26d

= -9+26×2

3

= -9+52

3

= -27+52

3

= - 25

3