The 7th term of an AP is 32 and it's 13th term is 62 find AP
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a7 = 32 and a13 = 62
From an – ak = (a + nd – d) – (a + kd – d)
= (n – k)d
a13 – a7 = (13 – 7)d = 62 – 32 = 30
6d = 30 d = 5
Now,
a7 = a + (7 – 1)5 = 32
a + 30 = 32
a = 2
Hence, the A.P is 2, 7, 12, 17
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