Question

The 7th term of an AP is 32 and its 13th term is 62. Find the AP.

Answer 1

Answer:

2,7,12,17,22,27,32..................

hope you got your answer

Answer 2

Answer:

2,7,12,17,22...... is the sequence in A.P.

Step-by-step explanation:

tn = a + (n-1)d ..... Formula

t7 = a + (7-1)d

32 = a + 6d ...... Equation 1

Similarly,

t13 = a + (13-1)d

62 = a + 12d ...... Equation 2

Subtracting equation 1 from equation 2,

  a + 12d = 62

-  a + 6d = 32

We get,

6d = 30

d = 30/6

d = 5

Substituting d = 5 in equation 1, we get,

a + 6d = 32

a + 6(5) = 32

a + 30 = 32

a = 32 - 30

a = 2

Therefore, first term = a = 2 and common difference = d = 5

Therefore, the sequence in an A.P. becomes 2,7,12,17,22......