Question

The 7th term of an AP is -4 and 13 term of that AP is -16. Find AP

Answer 1

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Answer 2

t7 = -4

a+6d = -4.......(i)

t13 = -16

a+12d = -16........(ii)

Subtracting equation (i) from (ii) we get:-

a+12d = -16

a +6d = -4

-. -. +

__________

6d = -12

d = -2

putting the value of d in equation (i) we get,

a-12 = -4

=> a = 8

So,

The A.P. is 8,6,4,2,0,-2,-4,-6.......

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