the 7th term of an Ap is-4 and it's 13th term is -16 find it S Ap
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A7= a+6d= -4 ...(i)
A13= a+12d= -16 ...(ii)
by linear equation in two variable
from (i) and (ii)
a+6d= -4
(-)a+(-)12d= -(+)16
-6d=12
d= -2
so by substituting d value as -2 in equation (i)
we get = a+6d= -4
a+6 (-2)= -4
a=-4+12
a= 8
there by the ap is..
a=8
d=-2
so the numbers are
8,6,4,2,0,-2,-4..............
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