The 7th term of an AP is -4 and it's 13th term is -16 . Find the A.P
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- 7th term of AP = -4
- 13th term of AP = -16
Let the First term of AP be a and Common difference be d.
As We know that How to find the any number of term of an AP using Tⁿ = a + (n-1)d as:
So, 7th term will be,
→ Tⁿ = a + (n-1)d
→ -4 = a + (7-1)d
→ -4 = a + 6d [1]
Again, 13th term will be,
→ -16 = a + (13-1)d
→ -16 = a + 12d [2]
After Calculating [1] and [2] Equation, we've got that d = -2.
→ -4 = a + 6d
→ -4 = a + 6 × (-2)
→ -4 = a -12
→ -4 +12 = a
→ a = 8
Hence, The AP will be 8,6,4... .
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