Question

the 7th term of an ap is -4 and its 13th term is -16 find the AP

Answer 1

Here your answer goes

Step :-  1

Let a be first term and d be the common difference of an AP

We have ,

$a_{7} = -4$ and $a_{13} = -16$

⇒  a + 6d = -4 ------>> 1

⇒  a + 12d = -16 ------->> 2

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⇒ 6d = - 12

⇒ d = -12/6

⇒ d = -2  

Step :- 2

Put the value of d in equation (1)

⇒ a +6d = -4

⇒ a + 6 (-2) = -4

⇒ a + (-12 ) = -4

⇒ a - 12 = -4

⇒ a = -4 + 12  

⇒ a = 8

Step :- 3

Since , a = 8 and d = -2 the AP will be

8 , 6 , 4, .........

↓↓↓

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Answer 2

a7 =-4
a13 =-16
a +6d =-4

a+12d =-16
-6d =12
d =-2
a =-4-6d
a =-4 +12
a =8
AP =8,6,4