Question

The 7th term of an AP is 4 times its 2nd term and 12th term is 2 more than 3 times
d of its 4th term. Find the AP.

Answer 1

Step-by-step explanation:

a7=4(a2)

a+6d=4(a+d)

a+6d=4a+4d

4a-a+4d-6d=0

3a-2d=0. eq. 01

a12=2+3(a4)

a+11d=2+3(a+3d)

a+11d=2+3a+9d

3a-a+9d-11d=-2

2a-2d=-2. eq.02

subtract eq02, 01

3a-2d=0

2a-2d=-2

we get,

a=2

and substitute it in eq 2

2a-2d=-2

2(2)-2d=-2

4-2d=-2

-2d=-2-4

d=-6/-2

d=3

so ap will be

a=2

a2=a+d=2+3=5

a3=a2+d=5+3=8

Answer 2

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Solution