the 7th term of an AP is 4 times its 2nd term and the twelfth term is 2 more than 3 times of its 4th term. find the AP
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Step-by-step explanation:
Let first term be a , and common difference be d.
7th term of AP = a+(7-1)d = a+6d
2nd term of AP = a+(2-1)d = a+d
12th term of AP = a+(12-1)d = a+11d
4th term of AP = a+(4-1)d = a+3d
Given
a+6d = 4(a+d)
a+6d = 4a+4d
2d = 3a ---------------------(1)
a+11d = 3(a+3d) +2
a+11d = 3a + 9d +2
-2a+2d = 2 -------------------(2)
Substitute 2d = 3a in 2
-2a+3a = 2
a = 2
Substitute a = 2/5 in 1
2d = (3*2)
d = 3
AP is 2,5,8,11,14
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