The 7th term of an arithmetic progression has the value 0 . Which term of the AP is 4 times the 13th element.
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The required A.P is
2, 5, 8, 11........................
Step-by-step explanation:
Formula used:
The n th term of the A.P a, a+d, a+2d, .......
is
Now we solve (1) and (2)
3a-2d=0.........(1)
2a-2d=-2.........(2)
(1)-(2)
a=2
using a=2 in (1) we get
3(2)-2d=0
2d=6
d=3
The required A.P is
2, 5, 8, 11........................
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