The 7th term of an as is -4and 13th term is -16find it's as
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Here is your answer,
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Let the first term be a , common difference be d and number of terms be n .
Tn = a+(n-1)d
T₇ = a+6d
=> -4 = a+6d -----------------(i)
T₁₃ = a+12d
=> -16 = a+12d ----------------(ii)
(ii) - (i)
6d = -16 - (-4)
=> 6d = -12
=> d = -2
Put d = -2 in (i)
-4 = a+6d
=> -4 = a -12
=> a = 8
The AP is 8,6,4,2,-2,-4,-6.........
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
Here is your answer,
______________________________________________________________
Let the first term be a , common difference be d and number of terms be n .
Tn = a+(n-1)d
T₇ = a+6d
=> -4 = a+6d -----------------(i)
T₁₃ = a+12d
=> -16 = a+12d ----------------(ii)
(ii) - (i)
6d = -16 - (-4)
=> 6d = -12
=> d = -2
Put d = -2 in (i)
-4 = a+6d
=> -4 = a -12
=> a = 8
The AP is 8,6,4,2,-2,-4,-6.........
______________________________________________________________
Hope this helped you !!
Please mark as brainliest !!
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