the 7th term of the A.P is -4 and its 13th term is -16. Find the A.P
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AP: 8,6,4,2,0....
a=first term
d=common difference
a=first term
d=common difference
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T7=a+6d
-4=a+6d
a=-4-6d. (1)
T13=a+12d
-16=at12d
From eq 1
-16=-4-6d+12d
-16+4=6d
-12=6d
d=-2
a=-4-6×-2
=-4+12
=8
Ap=a+d,a+2d,a+3d
Ap=6,4,2,.........nth term
-4=a+6d
a=-4-6d. (1)
T13=a+12d
-16=at12d
From eq 1
-16=-4-6d+12d
-16+4=6d
-12=6d
d=-2
a=-4-6×-2
=-4+12
=8
Ap=a+d,a+2d,a+3d
Ap=6,4,2,.........nth term
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