Question

the 7th term of the term is 32 and its 13th term is 63 find the a.p

Answer 1

Answer:

1 , 37/6 , 34/3...

Step-by-step explanation:

Let the first term be 'a' and common difference be 'd'

nth term = a + (n - 1)d

Here, 7th term is 32:

→ a + (7 - 1)d = 32

→ a + 6d = 32

→ a = 32 - 6d ... (1)

13th term is 63:

→ a + (13 - 1) = 63

→ a + 12d = 63

→ (32 - 6d) + 12d = 63

→ 32 - 6d + 12d = 63

→ 6d = 63 - 32 = 31

→ d = (31/6)

Therefore,

→ a = 32 - 6(31/6) = 32 - 31 = 1

Hence the AP is:

a = 1

a + d = 1 + (31/6) = 37/6

a + 2d = 1 + 2(31/6) = 34/3