Question

The 8 term of an ap is 0 prove that its 38 term is triple of its 18 term

Answer 1

Heya !!



8th term = 0


a + 7d = 0

a = -7d




To prove :- 38th term = 3 ( 18th term )



=> a + 37d = 3 ( a + 17d )




=> -7d + 37d = 3 ( -7d + 17d )




=> 30d = 3 ( 10d )



=> 30d = 30d


Hence,



38th term = 3 ( 18th term ).

Answer 2

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Given :-

a8 = 0

a + 7d = 0

To prove :-

a38 = 3 ( a18 )

Solution :-

a + 37 d = 3 ( a + 17 d )

Putting value of a

- 7 d + 37 d = 3 ( - 7d + 17 d )

30 d = 3 ( 10 d )

30 d = 30 d

Hence proved !!

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