Question

the 8 term of an Ap is 17 and 19 term is 39. find the Ap and the 25 term

Answer 1

a8=a+7d......(1)
17=a+7d
a19=a+18d
39=a+18d....(2)
now,on subtracting equation 1 from 2
we get d=2
then we substitute d=2 in equation 1
17=a+7×2
17-14=a
a=3
now AP is 3,5,7.......
25th term=a+24d
25th term=3+24(2)=51

Answer 2

HERE IS YOUR ANSWER MATE!!!!
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♥♥HOPE IT HELPS UHH!!!♥♥
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a8 = a+7d
=>17 = a+7d ....(1)
a19 = a+18d
=>39= a+18d .....(2)
subtracting (1) and (2)
=>a+7d=17
=>a+18d=39
- - -
__________
-11d= -22
d= 22/11
d=2
putting d=2 in eq...(1)
=> a+7(2)=17
=> a+14=17
=> a=17-14
=> a=3
AP:- 3,5,7....
a25=a+24d
=> a25=3+24(2)
=>a25=3+48
=>a25=51
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