the 8 term of an is 20 .the 15 term is 12 more than 11 term.find the ap
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Let a be the first term and d be the common difference of the AP.
Genereal term of an A.P.⇒a
n
=a+(n−1)d
We have, a
8
=31 and a
15
=16+a
11
⟹a+7d=31 and a+14d=16+a+10d
⟹a+7d=31 and 4d=16
⟹a+7d=31 and d=4⟹a+7×4=31
⟹a+28=31⟹a=3
Hence, the AP is a,a+d,a+2d,a+3d ...
i.e.,3, 7, 11, 15, 19, ...
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