Question

The 8th and 24th terms of an a.p. are 45 and 157 respectively , find the 33rd term.

Answer 1

Answer: the 33rd  term is 220.

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Step-by-step explanation:

a8 =45{Given}

⇒a+7d=45⟶(i)

{∵a=n =a+(n−1)d}

a24=157{Given}

⇒a+23d=157⟶(ii)

Subtracting eqn (i) from (ii), we have

a+23d−a−7d=157−45

16d=112

⇒d=7

Substituting the value of d in eq  

(i), we have

a+(7×7)=45

⇒a=45−49=−4

∴a  33  =a+32d

⇒=−4+(32×7)

⇒=−4+224

⇒a 33=220

Hence, the 33rd  term is 220.

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Answer 2

33rd term of a.p is 220

hope it's helpful