Question

The 8th one please...

Answer 1

Here numerator is x and denominator is y.

Its easy

First equation will be

x-y=-6

Second equation

4x-3y=-13 solve them and you will get answer

As x=5 and y=11

So fraction is 5 by 11

Answer 2

$\sf{Step-by-Step \: explanation:}$

Let the numerator be x

As, the denominator is 6 more than the numerator then let the numerator be x+6

x= $\dfrac{x+1}{x+6-3}$ = $\dfrac{3}{4}$

x= $\dfrac{x+1}{x+3}$ = $\dfrac{3}{4}$

x= 4(x+1) = 3(x+3)

x= 4x+4 = 3x+9

x= 4x-3x= 9-4

x= 5

If we see, before subtracting 3 from denominator and before adding 1 to the numerator the fraction was $\dfrac{5}{5+6}$

$\dfrac{5}{11}$

$\huge\bold{Verification:}$

$\dfrac{5+1}{5+6-3}$ = $\dfrac{3}{4}$

$\dfrac{6}{8}$ = $\dfrac{3}{4}$

Because of cancellation...

$\dfrac{3}{4}$ = $\dfrac{3}{4}$

Hence, the original fraction was, $\dfrac{5}{11}$ (Before making changes in adding and subtracting).
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
$\small\sf\orange{Thanks!!}$