Question

The 8th term of ab AP is 37and 12th term is 57 .find the AP

Answer 1

Hi,

Here is your answer,

Given data,

1. 8th term of an A.P is 37
2. 12th term of an A.P is 57

Now, a + 7d = 37 --------------> (1)

a + 11d = 57 -------------> (2)

Now, Solve using Elimination Method

4d = 20

d = 20/4 = 5

Now, Put d = 5 in Equation (1)

a + 7 * 5 = 37

a + 35 = 37

a = 37 - 35

a = 2

Therefore, the required A.P is 2,7,12,17

Hope it helps you !

Answer 2

*:..｡o○☆ HEYA MATE !☆○o｡..:*

GIVEN :

The 8th term of an AP is 37 .

The 12th term of an AP is 57.

TO FIND :

The AP

ANSWER :

The general term,tn =

$tn = a + (n - 1)d$

where n is the nth term.

a is the first term.

d is the common difference.

t8 = a + ( 8 - 1) d

a + 7d = 37 ________(1)

t12 = a + (12 - 1) d

a + 11d = 57 _________(2)

Subtract (1) & (2) ,

(2) => a + 11d = 57

(1) => a + 7d = 37

(-) (-) (-)

_________________

4d = 20

d = 20/4

d = 5 .

Substitute the value of d = 5 in equation (1),,,,

(1) => a + 7 (5) = 37

a + 35 = 37

a = 37 - 35

a = 2

The general form of an AP is ,,,,,

$ap \: = (a) + (a + d) + (a + 2d) + ..$

AP = 2 + ( 2 + 5) + ( 2 + 2 ×5) + ....

AP = 2 + 7+ 12 +....

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